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5th Grade Math Problem....Can You Solve It?

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Legend
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Posted: #76
In each backpack, there are 7 big cats. = 49 * 7 = 373 big cats

 
 
Prospect
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Posted: #77
2758 is correct !
 
MVP
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Posted: #78



 

This turned out to be one of the funniest threads ever.....shows how stupid people on covers can be. Shows how stupid people in general can be.

can't even do simple multiplication with some readin comprehension.

 

 
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Posted: #79

better yet....people keep answering even though the answer is in the thread!!!!!

 

 
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Posted: #80
i got 2758
 
Rookie
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Posted: #81
Regardless of how many legs, thats a hell of a lot of box
 
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Posted: #82
70
 
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Posted: #83

People still keep answering....

 
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Posted: #84
Quote Originally Posted by powerade:

People still keep answering....



Well we gotta know: is it cheetahs, leopards, or lions...since that makes all the difference
 
Legend
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Posted: #85

Quote Originally Posted by ragingstorm:

70

Only missed it by 10,920. 

 
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Posted: #86
10990
 
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Posted: #87
what is the square root of a Million?
 
Legend
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Posted: #88
1,000
 
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Posted: #89
Quote Originally Posted by HutchEmAll:

1,000



#Fuckscience 

It killed my magical elevator pulling Unicorns......
 
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Posted: #90

10,990 is definitely my final answer!

 
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Posted: #91
Quote Originally Posted by SirJohnDrake:

10,990 is definitely my final answer!


U sir are a Dope 

Smoke some weed and study your math books dummy
 
Captain
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Posted: #92
Are the backpacks on the bus?
 
Captain
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Posted: #93
If so, I have 10,990 as well.
 
Prospect
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Posted: #94
If it's a trick question I say 14...........cuz the cats n kittens don't have legs they're paws 
 
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Posted: #95

i hope this isnt a trick question beacuse of humans vs animals

the answer is simply 14 girls legs

 

7 girls X 7 back packs = 49 back packs

49 X 7 big cats = 343 big cats with 4 legs each = 1372 big cat legs + 14 girls legs = 1386 sub total legs

each big cat has 7 little cats 343 X 7 = 2401 little cats

X 4 legs each = 9604 lil cat legs +1386 girls and big cat legs =

grand total of 10,990 legs IN the BUS presuming  that all cats are in the backbacks and the backbacks are in THE bus !

IF not then the answer is only 14 legs are in the bus because the backpacks are not in the BUS but in cargo area !

 

this could be the trick to this question !

 
Covers Rehab
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Posted: #96
Let's have another math problem !!   Who's got one. 
 
Captain
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Posted: #97
most math questions like this require you read the question very carefully.  mathematical word problems I always found difficult as a kid.  I am sure a large number of people would get this type of question wrong based off of that. 
 
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Posted: #98
[Quote: Originally Posted by Dawnmarie]

i hope this isnt a trick question beacuse of humans vs animals

the answer is simply 14 girls legs

 

7 girls X 7 back packs = 49 back packs

49 X 7 big cats = 343 big cats with 4 legs each = 1372 big cat legs + 14 girls legs = 1386 sub total legs

each big cat has 7 little cats 343 X 7 = 2401 little cats

X 4 legs each = 9604 lil cat legs +1386 girls and big cat legs =

grand total of 10,990 legs IN the BUS presuming  that all cats are in the backbacks and the backbacks are in THE bus !

IF not then the answer is only 14 legs are in the bus because the backpacks are not in the BUS but in cargo area !

 

this could be the trick to this question !

[/QuoteYEAYYYYYYYYYYYv I got it right even tho it was already posted but i never saw the answer !

 

 

 
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Posted: #99
Shut up, bitch 
bigreds daddy
 
 
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Posted: #100

Here's the famous "birthday problem" - How many (randomly selected) people do you need in a room to have at least a 50% chance of at least 2 of them having the same birthdate (not year)?  This a college statistics problem and the answer will definitely surprise you!  If there is interest, move this to another thread!

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