Hey K, you know I've often (well maybe not often),but I have wondered how does one fade oneself? Do you just take the opposite of what you think you should take, and if so isn't that what you are then taking and should then take the opposite of that , which then puts us back to taking what we were originally taking?
Gawd Damn I gotta stop drinking so much coffee!!! I've twisted my mind up just thinking about it LOL.
Sorry, you'll have to forgive me, it's a slow day!!!
Good Luck Buddy, just keep your head up and take time on these slow days to think back to what you were doing to be successful before! Sometimes we need a break to clear the Noggin.
Cheers Bud! 
@rustie
Rust meant to ask u about post in peels thread...u mentioned factoring out juice when determining the % edge you think you have
For example do you mean on an even -110 line for each side instead of 52.3% suggested probability you consider it 50/50 as if there was no juice??
Thought it was an interesting comment/thought
@dubz4dummyz
Hey Dubz, what I was trying to convey was that if you remove the juice, as you have done in your example, you will see the true expected odds that the book perceives. What I was trying to say is that when we are working with such a small margin of Edge ( say 4%, which is what I use) , removing the juice which as you state in this case is 2.3% gives us a different result!
Let's say the odds are Visitor -110 / home -110 , (I'm going to use decimal odds as that's what I'm used to) so Home 1.909/Visitor 1.909 , that means each team is perceived to have a 52.4% chance of winning. Remove the juice and we have 50/50 chance of winning (+100 or 2.00 decimal) Now, you have done your homework and think the Home team has a 54.6% (-120 or 1.83 decimal)chance of winning.
As you can see if using a 4% edge as our cutoff ,this would not be a play if we don't remove the juice (54.6% minus 52.4% gives us a edge of only 2.2%), however the True odds of 50% means it would be a play (54.6 minus 50 gives us 4.6%). My thought is that when we are working with such a small % point it would be beneficial to remove the juice to see True Odds. Hope this helps.
Of course I could also be Totally wrong and just blowing smoke out my azz. 
Opinions?
And sorry K for hi-jacking your thread (it's temporary ,I assure you)
@rustie
That's what I thought u meant...
I just got thinking about it and how do you find the middle on different odds as the 1.909 and 1.909 is easy....
What if you are offered 1.80 and 1.95 for a line....how much juice do you take off the 1.80 compared to the 1.95...was having a hard time figuring out that situation even tho it may have an easy response
Kk, now remember I am not a math Wiz by any stretch of the imagination, but I'll try my best to explain.
Let's use todays Ottawa /New Jersey game for ex.
Odds currently 1.666 Ottawa, 2.35 N.Jersey
1.666 is 60% Implied Prob., 2.35 is 42.6% IP , adding these two together gets us 102.6% IP
To get true odds we need to get rid of the juice on each side , the formula for that is 60/(60+42.6)=58.5, this is Ottawa's true odds.
Inversely N.J. would be 42.6/(42.6+60)=41.5
This gets us to true odds of Ottawa 58.5% and NJ 41.5% for 100%
As you can see Ottawa is juiced at 1.5% ( 60%-58.5%=1.5%)and NJ at 1.1% (42.6%-41.5%=1.1%)
Easiest formula is Team A Implied Probability/(Team A IP + Team B IP)=
Team B IP/(Team B IP+ Team A IP)=
I hope this helps, and if I am incorrect I would hope that someone will please jump in and straighten me out. (Constructive criticism only please!)
Established in 1995,
)
so i feel ur pain 
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