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Have you heard anything about not getting payouts? I will agree that there customer service is the worst of any site I have tried. And there site is not the best set-up either. But I have done ok playing there games so far. I like the live BJ and even more...Baccarat. If those really are live games, then I feel better playing live instead of against a computer. They better payout though when I'm ready... |
ger19h | 32 |
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NVM...I finally got it. lol I was confusing myself so much. Guess it's not really ever possible guarantee that you get them all right, and at the same time make a profit. However, this could be used on parlays where you felt really confident about 2 or 3 picks and you wanted to throw in other picks you were not sure about. Then just pick the same 2 or 3 in the all parlays (and hope you were right) and then use different combinations for the other picks you were not as sure on. Maybe that would work. But guess there could always be upsets that would change everything. I get it now! |
After_I_Win | 54 |
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Well then ok...but tell me how many possible conbinations it would take to cover all possibilities of a 3 team parlay?
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After_I_Win | 54 |
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Quote Originally Posted by vvryan11: You telling me there are 128 different combinations for a 7-team parlay?
You guys are making this way too hard. I did too at first but its really simple. 6 teams total. 2 possible outcomes for each team. (either + or - the points /over under.. whatever) 2x2x2x2x2x2= 64 On a side note: I checked and...a $1 bet on a 12-team parlay would pay $1800.00...too bad I don't know the point total for every NFL game this week. lol |
After_I_Win | 54 |
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After reading the article, I basically found out the same thing I already knew--a 2 team parlay has only 4 possible combinations--one of them will be right. Then it talked alot about odds and how they always make a profit. But the example used only a 2 or 3 team parlay where the house will most certainly come out ahead. But, as you add more teams to the parlay...the win amount goes up...and if you add over 6...it really starts to move. So as the payouts go up, you have the ability to bet more and more possible parlay combinations (just like when we had 2 or 3, but were taking a loss), with higher payouts...my question is...can all the different parlay combinations be bet using let's say $1...and there be a point where the player would be able to profit... |
After_I_Win | 54 |
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Quote Originally Posted by vvryan11: Ok I will read it...thanks.
And no there are no other x number of team parlays that can cover themselves. Here's an article that shows actual odds of several x number of team parlays, even has house edge. https://www.hotstreaks.com/articles/35.asp Hope this helps. |
After_I_Win | 54 |
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Ok so all sites are different...one site said a $40 payout for a $1 bet on a 6 team parlay. And yes, I would like to know how you are coming up with the numbers. I don't really think it will work after thinking about it, but I want to know why it won't. lol An even easier way to look at it is do figure on the over/unders. I started with 2 teams and figured out that by doing 4 different parlays you could cover all possoble outcomes and win one parlay. But that would result in sure loss. So to get the payout higher, I just added more teams. For each additional team I added to the 6-team parlay I counted 8 more possible parlay combinations...not sure that it is right though. I simply added a let's say under bet, and an over bet for each additional team. Which is to say, 4 unders and 4 overs for each team added to the first 2 teams I started with. I know something has to be wrong with that way of doing it...but then what is it? And how many would it take to cover them all? How do you reach your figures? |
After_I_Win | 54 |
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I understand that the house has the edge. But I still would like to know how many different combinations it would take??? If one bet a dollar ($1) on a 6 team parlay...it should pay out about $44-46 if it is correct. So are you saying that there are more than let's say 44 different combinations in order to cover every possible scenerio of a 6-team parlay? Well how many does it take...if you have any ideas... |
After_I_Win | 54 |
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Very nice comments from some of you...thanks so much. For those of you who are saying NO IT WON'T WORK...would you care to explain mathematically why it won't. I'm not saying I am certain it is possible to cover every combination of a parlay...but if it's not...then prove me wrong with some numbers I can understand...don't just say it's not possible. Do half of you even understand what exactly it is I was actaully saying? I have thought about it and it seems like there would eventually be too many different combinations to cover them all without taking a sure loss. But I have not actually 100% determined that it's not possible... |
After_I_Win | 54 |
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Ok so here is how I was looking at it... If you bet on a 6 or 7 team parlay...and covered every possible combination...and bet a small amount on each...would that not turn a bit to profit? But in order to see if that would be realistic I need to know how many combinations would have to be used. For example: would one be able to cover every combination of a 6 team parlay...like I said above...with 36 different parlay combinations. If so, a dollar bet could be made on all 36 combinations...$36...and the payoff for a 6 team parlay would be greater than $36. So can it be done...that's the question? How many different combinations would have to be used? If it takes 63 or whatever, then that would mean a certain loss. But does it only take 36? I know it's confusing and I will have to sit down and work with it on paper...but I was just trying to see if anyone here had any ideas about it or knew if it would/would not work. |
After_I_Win | 54 |
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Oh...and almost forgot. I was just figuring to add 8 additional parlays for each additional game/team parlay. So I came out with a 6 team parlay (covering all possible combinations) to be 36 different parlays. Can someone prove this wrong? Thanks for any help!
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After_I_Win | 54 |
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If anyone wants me to explain something that is not clear above...I can answer any questions.
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After_I_Win | 54 |
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My brain is hurting trying to figure this out...so if you can help and explain that would be cool. Ok so this is about parlays (betting on multiple picks and they all must win or the parlay loses...I'm sure you all knew that). Ok so let's say I wanted to bet on multiple parlays so that I could hopefully get one right. Is there a way that anyone can think of in that you could bet on multiple parlays and cover every possible outcome from the different games you picked? I have tried to put this on paper, but my head hurts after trying to think of it...it's very confusing...for those mental ones amoung us...continue on... Ok so for an example: Let's start with a 2 team parlay using games. Let's say it was Dallas and Oakland; and Green Bay and Detroit on Thanksgiving. Now let's try to cover every possible outcome by betting parlays on those games. (I will use moneyline to make it easier). Ok so I figure that, to cover every possible outcome and guarantee a win, one would need to bet on 4 different parlays to cover the 2 team parlay. Let's say we pick Dallas and Green Bay to win in one parlay. Then the 2nd parlay would have to be Oak and Detroit in case of an upset. Now let's say Dal wins and Detroit wins--parlay 3. Then that leaves parlay 4 with Green Bay and Oak winning. So by betting on 4 different parlays, each possible winning combination has been covered. We will end up losing 3 of them, and winning 1. Now this is where it gets tricky. Let's say we want to add on more games. Let's say up to a 6 team parlay. Let's add on the other Thanksgiving Day game (NYG vs. Den). Ok so I figured that to make the 2 team parlay that we have correct above, into a 3 team parlay...all we would have to do is add a NYG win, and a Den win to each of the combinations above. This would require that we now use 12 parlays to cover all combinations (if I have it right). Because we have 4 parlays above and now we are making a new parlay for each different possible outcome. So does anyone know if it is possible to cover all possible outcomes of a 6 team parlay? And how many parlays would it take to have a correct combination in one of them? |
After_I_Win | 54 |
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Quote Originally Posted by DirtyBirds11:
Can you explain that one for me?
Using my newly discovered talent in reading these unusual numbers called lines/spread or whatever the heck u want to call it, I will do my best to assist u. ok so like u noted Port 99_Mav 104. ok so what we need to do here is a little substraction...everyone pull out ur calculators. 104 - 3.5 = 100.5. Wow im sure glad I had my mathematical instrument for that one--my head is hurting. So then if I were to understand the system correct this would put Dallas at 100.5 and Portland at 99. So if u picked Dallas u should have the WIN! I did notice that a scoreboard on this site had Dallas at 102 so maybe there was an error. NBA has it at 104...so dont worry, be happy...dont get me started. lol Ok so I think I covered it ...if my teachers above need to correct me please do. |
After_I_Win | 31 |
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Quote Originally Posted by AtlantaFalcon:
Like crushalot said, don't worry about the hockey money lines. Unless you plan on putting any sort of real money on hockey or baseball games, you won't have to really worry about what their lines mean. You can learn about it if you want, but it doesn't have much to do with this survivor game. Basically though, hockey and baseball games are so low scoring that it's kind of pointless to put a spread on their games, so they use the money line method instead. Hey thank u too! |
After_I_Win | 31 |
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Quote Originally Posted by crushalot22:
Doesnt mean shit. Just pick who wins in Baseball and Hockey cause those are money lines. Football and Basketball on Survivor will have pointspreads.
Why no questions asked when your second play covered the spread and your team lost the game, you were credited for a win....
Thanks! I get it now. lol |
After_I_Win | 31 |
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Quote Originally Posted by AtlantaFalcon:
I'm wondering if this thread is a joke thread. Either way, I think After_I_Win is a funny man. As far as the hockey -115, +105 lines go in your exhibit, you'd have to bet $115 to win $100 if you bet for Boston to win, and you'd win $105 if you bet $100 on Philadelphia. Anyone can correct me if I'm wrong since I'm kind of new to this thing myself. that dont make sense its not like the line in say basketball...what does the line mean for hockey if u were playing it on Survivor? |
After_I_Win | 31 |
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1 other question? if this whole line thing is right then what the heck does it go for in hockey??? I will now present to the court FIGURE A: EXHIBIT G:
NHL
so for tomorrows hocky game if say i pick Boston (which right now that very name is not cool with me) Boston would have to score 116 points more than philly??? In that case everyone better take the over! i know thats silly but what the heck does the line mean in this case??? |
After_I_Win | 31 |
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Thats WHAT that silly line stupid thing is! F*CK I thought i had won. So then Boston would have had to win by 4 for me to win? and if thats the case how in the world do peeps pick games that are like -13.5! it could easily go either way! i thought it was just pick the team! crap well there goes my streak of "3". anyone care to give some insight on this whole spread thing? So like if u think one team will surely win but the line is -13.5, am i understanding that the team must then win by 14 for me to get it right? But, say mabe i take the other team and they lose by 9, then i still win cuz they would have been +13.5? OH MAN DOES THIS JUST THROW A WHOLE NEW TWIST ON THINGS! anyone care to add anything to my reasoning or a helpful hint?
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After_I_Win | 31 |
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cmon guys im new to this a little help?
is it based on the spread thing which im just starting to figure out?
it was Boston -3
Plilly + 3
What does this mean? I picked Boston Celtics and they won 100-99! so I should have won right?
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After_I_Win | 31 |
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